Y=16x^2+.5+4x

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Solution for Y=16x^2+.5+4x equation: 



=16Y^2+.5+4Y

We move all terms to the left:

-(16Y^2+.5+4Y)=0

We get rid of parentheses

-16Y^2-4Y-.5=0

We add all the numbers together, and all the variables

-16Y^2-4Y-0.5=0

a = -16; b = -4; c = -0.5;
Δ = b2-4ac
Δ = -42-4·(-16)·(-0.5)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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